When the smaller of two consecutive integers is added to four times the larger, the result is 49. Find the two integers x = first consecutive integer x + 1 = second consecutive integer {consecutive integers increase by 1} x + 4(x + 1) = 49 {the smaller is added to 4 times the larger to equal 49} x + 4x + 4 = 49 {used distributive property} 5x + 4 = 49 {combined like terms} 5x = 45 {subtracted 4 form each side} x = 9 {divided each side by 5} x + 1 = 10 {substituted 9, in for x, into x + 1} 9 and 10 are the two consecutive integers  Algebra House
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