Find 2 consecutive even integers, such that their sum is equal to the difference of 3 times the larger and 2 times the smaller.

**x = first consecutive even integer**

x + 2 = second consecutive even integer{even integers are separated by 2}

x + 2 = second consecutive even integer

x + x + 2 = 3(x + 2) - 2x {their sum equals difference of 3 times larger and 2 times smaller}

2x + 2 = 3x + 6 - 2x {combined like terms and used distributive property}

2x + 2 = x + 6 {combined like terms}

x = 4 {subtracted x and 2 from each side}

x + 2 = 6 {substituted 4, in for x, into x + 2}

**4 and 6**are the two consecutive even integers

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