Find 2 consecutive even integers, such that their sum is equal to the difference of 3 times the larger and 2 times the smaller.
x = first consecutive even integer
x + 2 = second consecutive even integer {even integers are separated by 2} x + x + 2 = 3(x + 2)  2x {their sum equals difference of 3 times larger and 2 times smaller} 2x + 2 = 3x + 6  2x {combined like terms and used distributive property} 2x + 2 = x + 6 {combined like terms} x = 4 {subtracted x and 2 from each side} x + 2 = 6 {substituted 4, in for x, into x + 2} 4 and 6 are the two consecutive even integers Ask Algebra House Comments are closed.

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