Bruce has $5.50 in dimes and quarters. He has 8 more quarters then dimes. How many coins does he have? x = number of dimes x + 8 = number of quarters {he has 8 more quarters than dimes} 10x + 25(x + 8) = 550 {value of coin times number of coins equals total value} 10x + 25x + 200 = 550 {used distributive property} 35x + 200 = 550 {combined like terms} 35x = 350 {subtracted 200 from each side} x = 10 {divided each side by 35} x + 8 = 18 {substituted 8, in for x, into x + 8} 10 dimes and 18 quarters  Algebra House
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