How would you solve this by factoring? 3z2  48 = 0 I got it down to 3(z  4)(z + 4) = 0 But I don't know how to get the solution set.... please help? 3z2 48 = 0
3(z2 16) = 0 {factor 3 out} 3(z + 4)(z  4) = 0 {z2 16 is a difference of two squares} z + 4 = 0 or z  4 = 0 {set each factor equal to zero} z =  4 or z = 4 {solve each equation for z}  Algebra House
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