How do you solve this for x: x = √(3x - 12) + 4 x = √(3x - 12) + 4 x - 4 = √(3x - 12) {subtracted 4 from both sides} x² - 8x + 16 = 3x - 12 {squared both sides} x² - 11x + 28 = 0 {subtracted 3x and added 12 to both sides} (x - 4)(x - 7) = 0 {factored into two binomials} x - 4 = 0 or x - 7 = 0 {set each factor equal to 0} x = 4 or x = 7 {solved each equation for x} © Algebra House
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