How do you solve this for x:

x = √(3x - 12) + 4

x = √(3x - 12) + 4

x = √(3x - 12) + 4

x - 4 = √(3x - 12) {subtracted 4 from both sides}

x² - 8x + 16 = 3x - 12 {squared both sides}

x² - 11x + 28 = 0 {subtracted 3x and added 12 to both sides}

(x - 4)(x - 7) = 0 {factored into two binomials}

x - 4 = 0 or x - 7 = 0 {set each factor equal to 0}

**x = 4 or x = 7**{solved each equation for x}

*© Algebra House*