Solve the system of equations for x and y: y = 3x 2x  3y = 14 y = 3x 2x  3y = 14 2x  3(3x) = 14 {substituted 3x, in for y, into bottom equation} 2x  9x = 14 {multiplied 3 by 3x} 7x = 14 {combined like terms} x = 2 {divided both sides by 7} y = 3x {top equation} y = 3(2) {substituted 2, in for x, into top equation} y = 6 {multiplied} x = 2 and y = 6 the point of intersection would be (2,6) © Algebra House
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