Solve the system of equations for x and y: y = 3x 2x - 3y = 14 y = 3x 2x - 3y = 14 2x - 3(3x) = 14 {substituted 3x, in for y, into bottom equation} 2x - 9x = 14 {multiplied -3 by 3x} -7x = 14 {combined like terms} x = -2 {divided both sides by -7} y = 3x {top equation} y = 3(-2) {substituted -2, in for x, into top equation} y = -6 {multiplied} x = -2 and y = -6 the point of intersection would be (-2,-6) © Algebra House
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