√(x² + 12)  √(7x+2) = 0 √(x² + 12) = √(7x + 2) {added √(7x + 2) to both sides} x² + 12 = 7x + 2 {squared both sides} x²  7x + 10 = 0 {subtracted 7x and 2 from both sides} (x  5)(x  2) = 0 {factored into two binomials} x  5 = 0 or x  2 = 0 {set each factor equal to 0} x = 5 or x = 2 {solved each equation for x} © Algebra House
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