√(x² + 12) - √(7x+2) = 0
√(x² + 12) = √(7x + 2) {added √(7x + 2) to both sides}
x² + 12 = 7x + 2 {squared both sides}
x² - 7x + 10 = 0 {subtracted 7x and 2 from both sides}
(x - 5)(x - 2) = 0 {factored into two binomials}
x - 5 = 0 or x - 2 = 0 {set each factor equal to 0}
x = 5 or x = 2 {solved each equation for x}
© Algebra House
