How would you solve this for x? (5x² + 6x)(12x²  5x  2) = 0 5x² + 6x = 0 or 12x²  5x  2 = 0 {set each factor equal to 0} x(5x + 6) = 0 or (4x + 1)(3x  2) = 0 {factored x out of 1st and factored 2nd into two binomials} x = 0 or 5x + 6 = 0 or 4x + 1 = 0 or 3x  2 = 0 {again, set each factor equal to 0} x = 0 or 5x = 6 or 4x = 1 or 3x = 2 {started solving each equation for x} x = 0 or x =  6/5 or x = 1/4 or x = 2/3 {solved each equation for x} © Algebra House
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