Help graph... 6x + 5y= -30... my answer was -6/5x + 6, am I correct when graphing?

How do I graph it? Do I start at (0,6) than move 6 units down, 5 units to the right and plot, then what?

How do I graph it? Do I start at (0,6) than move 6 units down, 5 units to the right and plot, then what?

Get in slope-intercept form: y = mx + b

6x + 5y = -30

5y = -6x - 30 {subtracted 6x from both sides}

y = -6/5x - 6 {divided both sides by 5}

slope is -6/5 {number in front of x}

y-intercept is -6 {number without a variable}

To graph:

- start at the y-intercept, -6, and put a point

- from there, the slope is -6/5 (rise/run),

so go down 6 and to the right 5 and put another point,

then draw a line through the two points

- Algebra House

6x + 5y = -30

5y = -6x - 30 {subtracted 6x from both sides}

y = -6/5x - 6 {divided both sides by 5}

slope is -6/5 {number in front of x}

y-intercept is -6 {number without a variable}

To graph:

- start at the y-intercept, -6, and put a point

- from there, the slope is -6/5 (rise/run),

so go down 6 and to the right 5 and put another point,

then draw a line through the two points

- Algebra House