Help graph... 6x + 5y= 30... my answer was 6/5x + 6, am I correct when graphing? How do I graph it? Do I start at (0,6) than move 6 units down, 5 units to the right and plot, then what? Get in slopeintercept form: y = mx + b
6x + 5y = 30 5y = 6x  30 {subtracted 6x from both sides} y = 6/5x  6 {divided both sides by 5} slope is 6/5 {number in front of x} yintercept is 6 {number without a variable} To graph:  start at the yintercept, 6, and put a point  from there, the slope is 6/5 (rise/run), so go down 6 and to the right 5 and put another point, then draw a line through the two points  Algebra House
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