Help graph... 6x + 5y= -30... my answer was -6/5x + 6, am I correct when graphing? How do I graph it? Do I start at (0,6) than move 6 units down, 5 units to the right and plot, then what? Get in slope-intercept form: y = mx + b
6x + 5y = -30 5y = -6x - 30 {subtracted 6x from both sides} y = -6/5x - 6 {divided both sides by 5} slope is -6/5 {number in front of x} y-intercept is -6 {number without a variable} To graph: - start at the y-intercept, -6, and put a point - from there, the slope is -6/5 (rise/run), so go down 6 and to the right 5 and put another point, then draw a line through the two points - Algebra House
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