Graphing from Slope-Intercept Form

Help graph... 6x + 5y= -30... my answer was -6/5x + 6, am I correct  when graphing?
How do I graph it?  Do I start at (0,6) than move 6 units down, 5 units to the right and plot, then what?

Get in slope-intercept form: y = mx + b
6x + 5y = -30
5y = -6x - 30 {subtracted 6x from both sides}
y = -6/5x - 6 {divided both sides by 5}

slope is -6/5 {number in front of x}
y-intercept is -6 {number without a variable}

To graph:
- start at the y-intercept, -6, and put a point
- from there, the slope is -6/5 (rise/run),
so go down 6 and to the right 5 and put another point,
then draw a line through the two points

- Algebra House