The formula for the perimeter of a rectangle is P = 2L + 2W. The perimeter of the local high school soccer field is 268 feet. The length is 34 ft longer than the width. Find the dimensions of the soccer field.
Perimeter = 2(length) + 2(width)
x = width
x + 34 = length
2x + 2(x + 34) = 268 {perimeter is 2(width) + 2(length)}
2x + 2x + 68 = 268 {used distributive property}
4x + 68 = 268 {combined like terms}
4x = 200 {subtracted 68 from both sides}
x = 50 {divided both sides by 4}
x + 34 = 84 {substituted 50, in for x, into x + 34}
width = 50 ft
length = 84 feet
© Algebra House
x = width
x + 34 = length
2x + 2(x + 34) = 268 {perimeter is 2(width) + 2(length)}
2x + 2x + 68 = 268 {used distributive property}
4x + 68 = 268 {combined like terms}
4x = 200 {subtracted 68 from both sides}
x = 50 {divided both sides by 4}
x + 34 = 84 {substituted 50, in for x, into x + 34}
width = 50 ft
length = 84 feet
© Algebra House
