A rectangle has a length of 12 and a width of 2x. If the area of the rectangle is 12, what is the rectangle's perimeter?

width = 2x

length = 12

area = 12

Area of a rectangle = length x width

2x(12) = 2x {area is length x width}

24x = 12 {multiplied}

x = 0.5 {divided each side by 24}

2x = 1 = width {substituted 0.5, in for x, into 2x}

width = 1 and length = 12

Perimeter of a rectangle is 2(width) + 2(length)

= 2(1) + 2(12) {substituted length and width into perimeter formula}

= 2 + 24 {multiplied}

= 26 {added}

**Perimeter is 26**

{a shortcut would be to identify that the length was the same as the area,

therefore the width would have to be 1}

*- Algebra House*