A rectangle has a length of 12 and a width of 2x. If the area of the rectangle is 12, what is the rectangle's perimeter? width = 2x length = 12 area = 12 Area of a rectangle = length x width 2x(12) = 2x {area is length x width} 24x = 12 {multiplied} x = 0.5 {divided each side by 24} 2x = 1 = width {substituted 0.5, in for x, into 2x} width = 1 and length = 12 Perimeter of a rectangle is 2(width) + 2(length) = 2(1) + 2(12) {substituted length and width into perimeter formula} = 2 + 24 {multiplied} = 26 {added} Perimeter is 26 {a shortcut would be to identify that the length was the same as the area, therefore the width would have to be 1}  Algebra House
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