The perimeter of a rectangle is 310 m. The length is 25 m greater than the width.

What are the length and width of the rectangle?

What are the length and width of the rectangle?

x = width

x + 25 = length

2x + 2(x + 25) = 310 {2 times width plus 2 times length = perimeter}

2x + 2x + 50 = 310 {used distributive property}

4x + 50 = 310 {combined like terms}

4x = 260 {subtracted 50 from both sides}

x = 65 m width {divided both sides by 4}

x + 25 = 90 m length {substituted 65 in for x}

- Algebra House

x + 25 = length

2x + 2(x + 25) = 310 {2 times width plus 2 times length = perimeter}

2x + 2x + 50 = 310 {used distributive property}

4x + 50 = 310 {combined like terms}

4x = 260 {subtracted 50 from both sides}

x = 65 m width {divided both sides by 4}

x + 25 = 90 m length {substituted 65 in for x}

- Algebra House