A man has $185 in five and ten dollar bills. How many of each did he has if he had 7 more fives than tens? x = number of ten dollar bills x + 7 = number of five dollar bills {he has 7 more fives than tens} 10x + 5(x + 7) = 185 {value of bill times number of bills equals total value} 10x + 5x + 35 = 185 {used distributive property} 15x + 35 = 185 {combined like terms} 15x = 150 {subtracted 35 from each side} x = 10 {divided each side by 15} x + 7 = 17 {substituted 10, in for x, into x + 7} 10 ten dollar bills 17 five dollar bills  Algebra House Comments are closed.

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