Fred is 4 times as old as his niece, Selma. Ten years from now, he will be twice as old as she will be. How old is each now? x = Selma's age now
4x = Fred's age now {Fred is 4 times as old as Selma} x + 10 = Selma's age in 10 years 4x + 10 = Fred's age in 10 years 4x + 10 = 2(x + 10) {his age in 10 yrs is twice her age in 10 years} 4x + 10 = 2x + 20 {used distributive property} 2x + 10 = 20 {subtracted 2x from both sides} 2x = 10 {subtracted 10 from both sides} x = 5 {divided both sides by 2} 4x = 20 {substituted 5, in for x, into 4x} Selma is 5 now Fred is 20 now  Algebra House
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