Find four consecutive integers whose sum is 86.

x = 1st

x + 1 = 2nd

x + 2 = 3rd

x + 3 = 4th

x + x + 1 + x + 2 + x + 3 = 86 {sum is 86}

4x + 6 = 86 {combined like terms}

4x = 80 {subtracted 6 from both sides}

x = 20 {divided both sides by 4}

x + 1 = 21

x + 2 = 22

x + 3 = 23

- Algebra House

x + 1 = 2nd

x + 2 = 3rd

x + 3 = 4th

x + x + 1 + x + 2 + x + 3 = 86 {sum is 86}

4x + 6 = 86 {combined like terms}

4x = 80 {subtracted 6 from both sides}

x = 20 {divided both sides by 4}

x + 1 = 21

x + 2 = 22

x + 3 = 23

- Algebra House