Find four consecutive integers whose sum is 86. x = 1st
x + 1 = 2nd x + 2 = 3rd x + 3 = 4th x + x + 1 + x + 2 + x + 3 = 86 {sum is 86} 4x + 6 = 86 {combined like terms} 4x = 80 {subtracted 6 from both sides} x = 20 {divided both sides by 4} x + 1 = 21 x + 2 = 22 x + 3 = 23  Algebra House
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