Find four consecutive integers whose sum is 86.
x = 1st
x + 1 = 2nd
x + 2 = 3rd
x + 3 = 4th
x + x + 1 + x + 2 + x + 3 = 86 {sum is 86}
4x + 6 = 86 {combined like terms}
4x = 80 {subtracted 6 from both sides}
x = 20 {divided both sides by 4}
x + 1 = 21
x + 2 = 22
x + 3 = 23
- Algebra House
x + 1 = 2nd
x + 2 = 3rd
x + 3 = 4th
x + x + 1 + x + 2 + x + 3 = 86 {sum is 86}
4x + 6 = 86 {combined like terms}
4x = 80 {subtracted 6 from both sides}
x = 20 {divided both sides by 4}
x + 1 = 21
x + 2 = 22
x + 3 = 23
- Algebra House
