For the function f(x) = x² - 6x + 8,

Find the y-intercept, the equation of the axis of symmetry, and the x-coordinate of the vertex.

Find the y-intercept, the equation of the axis of symmetry, and the x-coordinate of the vertex.

**f(x) = x² - 6x + 8**

The

**y-intercept is 8**.

The function is in the form f(x) = ax² + bx + c

a = 1, b = -6, and c = 8

-b

---- = x {equation of axis of symmetry}

2a

-(-6)

------- = x {substituted given information into equation}

2(1)

6

--- = x {simplified}

2

x = 3 {divided}

**The equation of the axis of symmetry is x = 3**.

The vertex is located on the axis of symmetry, therefore

the

**x-coordinate of the vertex is 3**.

*- Algebra House*