For the function f(x) = x² - 6x + 8, Find the y-intercept, the equation of the axis of symmetry, and the x-coordinate of the vertex. f(x) = x² - 6x + 8 The y-intercept is 8. The function is in the form f(x) = ax² + bx + c a = 1, b = -6, and c = 8 -b ---- = x {equation of axis of symmetry} 2a -(-6) ------- = x {substituted given information into equation} 2(1) 6 --- = x {simplified} 2 x = 3 {divided} The equation of the axis of symmetry is x = 3. The vertex is located on the axis of symmetry, therefore the x-coordinate of the vertex is 3. - Algebra House
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