For the function f(x) = x²  6x + 8, Find the yintercept, the equation of the axis of symmetry, and the xcoordinate of the vertex. f(x) = x²  6x + 8 The yintercept is 8. The function is in the form f(x) = ax² + bx + c a = 1, b = 6, and c = 8 b  = x {equation of axis of symmetry} 2a (6)  = x {substituted given information into equation} 2(1) 6  = x {simplified} 2 x = 3 {divided} The equation of the axis of symmetry is x = 3. The vertex is located on the axis of symmetry, therefore the xcoordinate of the vertex is 3.  Algebra House
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