How do you find the vertex of f(x) = (x + 3)² ?

Vertex form of a quadratic function is f(x) = a(x - h)² + k

The vertex has coordinates of (h,k)

In f(x) = (x + 3)²

Since 3 is positive, that means the value of h is -3.

To make +3, it would have to be x - (-3), in vertex form.

The value of k is, of course, 0.

The vertex has coordinates of (h,k)

In f(x) = (x + 3)²

Since 3 is positive, that means the value of h is -3.

To make +3, it would have to be x - (-3), in vertex form.

The value of k is, of course, 0.

**Vertex has coordinates of (-3,0)**{as you see in the graph below}

or

*See more function examples*__here__or

*Ask Algebra House*