Finding the missing lengths of a triangle

In triangle A, the longer leg is 4 more than the shorter leg, and the hypotenuse is 4 more then the longer leg. How do you find the short leg, the long leg, and the hypotenuse.

x = shorter leg
x + 4 = longer leg
x + 8 = hypotenuse {it is 4 more than longer leg}

a² + b² = c² {pythagorean theorem}

x² + (x + 4)² = (x + 8)²   {substituted into pythagorean theorem}
x² + x² + 8x + 16 = x² + 16x + 64   {used foil method}
2x² + 8x + 16 = x² + 16x + 64    {combined like terms}
x² - 8x - 48 = 0   {subtracted x², 16x, and 64 from both sides}
(x - 12)(x + 4) = 0   {factored into two binomials}
x - 12 = 0 or x + 4 = 0   {set each factor equal to 0}
x = 12 or x = -4   {solved each equation for x}
x = 12   {length of a side cannot be negative}
x + 4 = 16   {substituted 16, in for x, into x + 4}
x + 8 = 20   {substituted 12, in for x, into x + 8}

short leg = 12
long leg = 16
hypotenuse = 20

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