Four times a number added to another number is 36. Three times the first number minus the other number is 20. Can you please tell me the numbers? x = the number y = other number 4x + y = 36 {four times a number added to another number is 36} 3x  y = 20 {three times the 1st minus other is 20}  7x = 56 {added the two equations together and eliminated the y} x = 8 {divided both sides by 7} The first number is 8 4x + y = 36 {top equation} 4(8) + y = 36 {substituted 8 in for x} 32 + y = 36 {multiplied 4 by 8} y = 4 {subtracted 32 from both sides} The other number is 4 8 and 4 are the two numbers  Algebra House
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