Find three consecutive integers such that the sum of the first and three times the second is 44 less than five times the third. x = first consecutive integer x + 1 = second consecutive integer {consecutive integers increase by 1} x + 2 = 3rd consecutive integer x + 3(x + 1) = 5(x + 2)  44 {sum of 1st and 3 times 2nd is 44 less than 3 times the 3rd} x + 3x + 3 = 5x + 10  44 {used distributive property} 4x + 3 = 5x  34 {combined like terms} 3 = x  34 {subtracted 4x from each side} x = 37 {added 34 to each side} x + 1 = 38 {substituted 37, in for x, into x + 1} x + 2 = 39 {substituted 37, in for x, into x + 2} 37, 38, and 39 are the three consecutive integers  Algebra House
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