Find three consecutive integers

Find three consecutive integers, such that twice the first added to the last is 23.

x = first integer
x + 1 = second integer
x + 2 = 3rd integer 

2x + x + 2 = 23 {twice the first added to the last is 23}
3x + 2 = 23 {combined like terms}
3x = 21 {subtracted 2 from each side}
x = 7 {divided each side by 3}
x + 1 = 8 {substituted 7 for x}
x + 2 = 9 {substituted 7 for x} 

7,8, and 9 are the three consecutive integers

- Algebra House