Find three consecutive integers, such that twice the first added to the last is 23. x = first integer
x + 1 = second integer x + 2 = 3rd integer 2x + x + 2 = 23 {twice the first added to the last is 23} 3x + 2 = 23 {combined like terms} 3x = 21 {subtracted 2 from each side} x = 7 {divided each side by 3} x + 1 = 8 {substituted 7 for x} x + 2 = 9 {substituted 7 for x} 7,8, and 9 are the three consecutive integers  Algebra House
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