Find three consecutive integers whose sum is 114. x = 1st x + 1 = 2nd {consecutive integers increase by 1 each time} x + 2 = 3rd x + x + 1 + x + 2 =  114 {their sum is 114} 3x + 3 = 114 {combined like terms} 3x = 117 {subtracted 3 from both sides} x = 39 {divided both sides by 3} x + 1 = 38 {substituted 39, in for x, into x + 1} x + 2 = 37 {substituted 39, in for x, into x + 2} 39, 38, and 37 are the three consecutive integers © Algebra House
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