How do you get the equation of the line that: passes through the point ( 4, 11) and has a slope of 3/4? Pointslope form is y  y1 = m(x  x1) m is the slope (x1,y1) are the coordinates of the given point ( 4,11), m = 3/4 y  11 = (3/4)[x  (4)] {substituted into pointslope form} y  11 = (3/4)(x + 4) {simplified double negative signs} y  11 = (3/4)x  3 {used distributive property} y = (3/4)x + 8 {added 11 to both sides} © Algebra House
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