An eagle is 4 times as old as a falcon. Three years ago, the eagle was 7 times as old as the falcon.

Find the present age of each bird.

Find the present age of each bird.

x = falcon's age now

4x = eagle's age now {the eagle is 4 times as old as falcon}

x - 3 = falcon's age 3 years ago

4x - 3 = eagle's age 3 years ago

4x – 3 = 7(x – 3) {three years ago, eagle was 7 times the falcon}

4x – 3 = 7x – 21 {used distributive property}

4x = 7x -18 {added 3 to both sides}

-3x = -18 {subtracted 7x from both sides}

x = 6 {divided both sides by -3}

4x = 24 {substituted 6, in for x, into 4x}

4x = eagle's age now {the eagle is 4 times as old as falcon}

x - 3 = falcon's age 3 years ago

4x - 3 = eagle's age 3 years ago

4x – 3 = 7(x – 3) {three years ago, eagle was 7 times the falcon}

4x – 3 = 7x – 21 {used distributive property}

4x = 7x -18 {added 3 to both sides}

-3x = -18 {subtracted 7x from both sides}

x = 6 {divided both sides by -3}

4x = 24 {substituted 6, in for x, into 4x}

**falcon is 6 now**

eagle is 24 noweagle is 24 now

*- Algebra House*