Find the dimensions of a rectangle whose length is 40 inches more than its width and whose perimeter is 300 in? x = width
x + 40 = length {length is 40 more than width} x + x + x + 40 + x + 40 = 300 {got perimeter by adding all sides} 4x + 80 = 300 {combined like terms} 4x = 220 {subtracted 80 from both sides} x = 55 inches {width} x + 40 = 95 inches (length)  Algebra House
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