What are three consecutive odd integers whose sum is equal to five more than two times the second largest number among the three numbers? x = first x + 2 = second x + 4 = third {odd integers increase by 2 each time} x + x + 2 + x + 4 = 2(x + 2) + 5 {sum is five more than two times second largest} 3x + 6 = 2x + 4 + 5 {used distributive property and combined like terms} 3x + 6 = 2x + 9 {combined like terms on right side} x = 3 {subtracted 2x and subtracted 6 from each side} x + 2 = 5 {substituted 5, in for x, into x + 2} x + 4 = 7 {substituted 3, in for x, into x + 4} 3,5, and 7 are the three consecutive odd integers  Algebra House
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