Harold has $4.35 of change in quarters and dimes, with 5 more dimes than quarters. How many of each coin does he have?

**x = number of quarters**

**x + 5 = number of dimes**{there are 5 more dimes than quarters}

25x + 10(x + 5) = 435 {number of coins times value of coin equals total value}

25x + 10x + 50 = 435 {used distributive property}

35x + 50 = 435 {combined like terms}

35x = 385 {subtracted 50 from each side}

x = 11 {divided each side by 35}

x + 5 = 16 {substituted 11, in for x, into x + 5}

**11 quarters and 16 dimes**

*- Algebra House*