Mark has a total of 41 coins consisting of nickels and quarters the total value of the coins is $4.85. How many of each type of coin does he have?
x = number of nickels
41  x = number of quarters {there are a total of 41 coins} .05x + .25(41  x) = 4.85 {value of coin times number of coins equals total value} .05x + 10.25  .25x = 4.85 {used distributive property} .02x + 10.25 = 4.85 {combined like terms} .02x = 5.4 {subtracted 10.25 from each side} x = 27 {divided each side by .02} 41  x = 14 {substituted 27, in for x, into 41  x} 27 nickels and 14 quarters Ask Algebra House Comments are closed.

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