Mark has a total of 41 coins consisting of nickels and quarters the total value of the coins is $4.85. How many of each type of coin does he have?

x = number of nickels

41 - x = number of quarters {there are a total of 41 coins}

.05x + .25(41 - x) = 4.85 {value of coin times number of coins equals total value}

.05x + 10.25 - .25x = 4.85 {used distributive property}

-.02x + 10.25 = 4.85 {combined like terms}

-.02x = -5.4 {subtracted 10.25 from each side}

x = 27 {divided each side by -.02}

41 - x = 14 {substituted 27, in for x, into 41 - x}

41 - x = number of quarters {there are a total of 41 coins}

.05x + .25(41 - x) = 4.85 {value of coin times number of coins equals total value}

.05x + 10.25 - .25x = 4.85 {used distributive property}

-.02x + 10.25 = 4.85 {combined like terms}

-.02x = -5.4 {subtracted 10.25 from each side}

x = 27 {divided each side by -.02}

41 - x = 14 {substituted 27, in for x, into 41 - x}

**27 nickels and 14 quarters**

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