Mike has $1.75 in dimes and nickels. If he has 5 more nickels than dimes, how many of each coin does he have? x = number of dimes x + 5 = number of nickels {5 more nickels than dimes} 10x + 5(x + 5) = 175 {value of each x number of each = total value of each} 10x + 5x + 25 = 175 {used distributive property} 15x + 25 = 175 {combined like terms} 15x = 150 {subtracted 25 from both sides} x = 10 {divided both sides by 15} x + 5 = 15 {substituted 10, in for x, into x + 5} 10 dimes and 15 nickels  Algebra House
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