Is (1,5) a solution of the system?

5x - 2y = -5

3x - 7y = -32

5x - 2y = -5

3x - 7y = -32

Substitute (1 in for x) and (5 in for y) into both equations. If you get a true statement, then it is a solution for that equation.

5(1) - 2(5) = -5 {substituted coordinates into first equation}

5 - 10 = -5 {multiplied 5 by 1 and -2 by 5}

-5 = -5 {combined like terms}

- works in first equation {makes a true statement}

3(1) - 7(5) = -32 {substituted coordinates into first equation}

3 - 35 = -32 {multiplied 3 by 1 and -7 by 5}

-32 = -32 {combined like terms}

- works in second equation {makes a true statement}

Both equations yield true statements when you substitute in,

therefore it is a solution of the system

© Algebra House

5(1) - 2(5) = -5 {substituted coordinates into first equation}

5 - 10 = -5 {multiplied 5 by 1 and -2 by 5}

-5 = -5 {combined like terms}

- works in first equation {makes a true statement}

3(1) - 7(5) = -32 {substituted coordinates into first equation}

3 - 35 = -32 {multiplied 3 by 1 and -7 by 5}

-32 = -32 {combined like terms}

- works in second equation {makes a true statement}

Both equations yield true statements when you substitute in,

therefore it is a solution of the system

© Algebra House