A man is 4times as old as her daughter. After 16years, he will be twice as old as his daughter. Find the daughter’s age. x = daughter's age now
4x = man's age now {man is 4 times as old as daughter} x + 16 = daughter in 16 years 4x + 16 = man in 16 years 4x + 16 = 2(x + 16) {after 16 years, he will be twice as old as her} 4x + 16 = 2x + 32 {used distributive property} 4x = 2x + 16 {subtracted 16 from both sides} 2x = 16 {subtracted 2x from both sides} x = 8 {divided both sides by 2} 4x = 32 {substituted 8, in for x, into 4x} x = 8 {divided both sides by 4} daughter is 8  Algebra House
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