Mon is 8 years younger than Ram. In two years, the age of Ram will be 2 less than twice Mon’s age. Find their present ages. x = Ram's present age x  8 = Mon's present age {Mon is 8 younger than Ram} x + 2 = Ram's age in 2 years {added 2 onto present age} x  6 = Mon's age in 2 years {added 2 onto present age} x + 2 = 2(x  6)  2 {in two years, Ram will be 2 less than twice Mon} x + 2 = 2x  12  2 {used distributive property} x + 2 = 2x  14 {combined like terms} 2 = x  14 {subtracted x from each side} x = 16 {added 14 to each side} x  8 = 8 {substituted 16, in for x, into x  8} Ram is 16 and Mon is 8  Algebra House
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