Mon is 8 years younger than Ram. In two years, the age of Ram will be 2 less than twice Mon’s age. Find their present ages.

x = Ram's present age

x - 8 = Mon's present age {Mon is 8 younger than Ram}

x + 2 = Ram's age in 2 years {added 2 onto present age}

x - 6 = Mon's age in 2 years {added 2 onto present age}

x + 2 = 2(x - 6) - 2 {in two years, Ram will be 2 less than twice Mon}

x + 2 = 2x - 12 - 2 {used distributive property}

x + 2 = 2x - 14 {combined like terms}

2 = x - 14 {subtracted x from each side}

x = 16 {added 14 to each side}

x - 8 = 8 {substituted 16, in for x, into x - 8}

x - 8 = Mon's present age {Mon is 8 younger than Ram}

x + 2 = Ram's age in 2 years {added 2 onto present age}

x - 6 = Mon's age in 2 years {added 2 onto present age}

x + 2 = 2(x - 6) - 2 {in two years, Ram will be 2 less than twice Mon}

x + 2 = 2x - 12 - 2 {used distributive property}

x + 2 = 2x - 14 {combined like terms}

2 = x - 14 {subtracted x from each side}

x = 16 {added 14 to each side}

x - 8 = 8 {substituted 16, in for x, into x - 8}

**Ram is 16 and Mon is 8***- Algebra House*