Solve the inequality: 2x  1 < 7 Absolute value is the distance away from zero. 2x  1 < 7 {the distance (2x  1) is from zero, is less than 7} The two numbers that are 7 away from zero are 7 and 7. Therefore, (2x  1) is between 7 and 7. 7 < 2x  1 < 7 {the value of (2x  1) lies between 7 and 7} +1 +1 +1 6 < 2x < 8 {added 1 to the left, the middle, and the right} 3 < x < 4 {divided the left, middle, and right by 2}  Algebra House Comments are closed.

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