A baseball diamond

A baseball diamond is a square 30 yd on a side. If you were on second base and you wanted to throw the ball to the catcher, who stands at home plate, how far would you have to throw the ball?

Use the Pythagorean Theorem ---> a² + b² = c²

a and b are the legs, c is the hypotenuse   {across from the right angle}
a and b would be ....home to 1st....and 1st to 2nd
c would be..... 2nd to home   {the right angle is at 1st base}

30² + 30² = c²   {substituted into Pythagorean Theorem}
900 + 900 = c²   {squared the 30's}
1800 = c²   {added 900 and 900}
c ≈ 42.43 yds   {evaluated square root of 1800 and rounded}

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