Write an equation that is parallel to 3x â 2y = 14 and passes through the point (6, 11) in slopeintercept form.
Parallel lines have the same slope. Get the given equation in slopeintercept form to find the slope.
Slopeintercept form is y = mx + b m is the slope b is the yintercept 3x  2y = 14 {given equation} 2y = 3x + 14 {subtracted 3x from each side} y = (2/3)x  7 {divided each side by 2} slope = 2/3 Use slopeintercept form, with the point and the slope, to get the equation of the line. Substitute (6,11) in for x and y, and 2/3 in for the slope. Find the yintercept, then substitute it back in, with the slope, into slopeintercept form. (6,11), m = 2/3 {point and slope} y = mx + b {slopeintercept form} 11 = (2/3)(6) + b {substituted point and slope into slopeintercept form} 11 = 4 + b {multiplied 2/3 by 6} b = 7 {added 4 to each side} yintercept is 7 y = mx + b {slopeintercept form} y = (2/3)x  7 {substituted point and slope into slopeintercept form} Use the graphing calculator to check if the point does lie on the new line.
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