A globe has a diameter of 12 inches. It fits inside a cubeshaped box that has a side length of 12 inches. What is the volume, rounded to the nearest hundredth of a cubic inch, of the space inside the box that is not taken up by the globe? Round your answer to 2 digits.
Volume of the box
V = length x width x height = 12 x 12 x 12 = 1728 in³ Volume of the globe (sphere) V = (4/3)πr³ = (4/3)(3.14)(6³) {substituted 3.14 for π and 6 for r, the radius} = (4/3)(3.14)(216) {evaluated the exponent) ≈ 904.32 in³ {multiplied} Subtract the volume of the globe from the volume of the box: 1728  904.32 ≈ 823.68 in³ Ask a Question
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