A globe has a diameter of 12 inches. It fits inside a cubeshaped box that has a side length of 12 inches.
What is the volume, rounded to the nearest hundredth of a cubic inch, of the space inside the box that is not taken up by the globe?
Find the volume of the globe, which is a sphere. V = (4/3)πr³
Find the volume of the box. V = s³ {one side cubed} Subtract the volume of the globe from the volume of the box. Volume of the globe V = (4/3)πr³ = (4/3)(3.14)(6³) {since the diameter is 12, the radius is 6} = (4/3)(3.14)(216) {evaluated the exponent} ≈ 904.32 {multiplied} Volume of box V = s³ {one side cubed} = 12³ {substituted 12 in for s} = 1728 {evaluated exponent} Volume of space inside box not taken up by globe = 1728  904.32 {subtracted volume of sphere from volume of box} = 823.68 in³ {subtracted} Ask Algebra House
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