What is the slope and y-intercept after the dilation?

12x -2y = 6 , a dilation centered at the origin with a scale factor of 4 is applied to the line.  What is the slope
and y-intercept after the dilation?

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Get the original equation in slope-intercept form.

12x - 2y = 6
-2y = -12x + 6  {subtracted 12x from each side}
y = 6x - 3   {divided each side by -2}
slope = 6
y-intercept = -3

Choose a point on that line, such as the y-intercept (0,-3)

Count the distance from the center of dilation, to that point.
From (0,0) to (0,-3) is 3.

Multiply the distance by the scale factor of 4….. 3 x 4 = 12.
Count 12 away from the center of dilation.  (0,-12) is the new y-intercept, and the slope is always the same
when dilating lines.  Dilations make lines parallel.

y = 6x - 12 is the new line after the dilation

slope = 6
y-intercept = -12

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