12x -2y = 6 , a dilation centered at the origin with a scale factor of 4 is applied to the line. What is the slope
and y-intercept after the dilation?
Get the original equation in slope-intercept form.
12x - 2y = 6 -2y = -12x + 6 {subtracted 12x from each side} y = 6x - 3 {divided each side by -2} slope = 6 y-intercept = -3 Choose a point on that line, such as the y-intercept (0,-3) Count the distance from the center of dilation, to that point. From (0,0) to (0,-3) is 3. Multiply the distance by the scale factor of 4….. 3 x 4 = 12. Count 12 away from the center of dilation. (0,-12) is the new y-intercept, and the slope is always the same when dilating lines. Dilations make lines parallel. y = 6x - 12 is the new line after the dilation slope = 6 y-intercept = -12 Ask Algebra House
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