What is an equation of the line that passes through the point (-8,0) and is parallel to the line x + 2y = 14?
Parallel lines have equal slopes. Get the equation in slope-intercept form, so that you can identify the slope of the line. Then, use that slope with the given point to get the equation of the line.
Slope-intercept form is y = mx + b m is the slope b is the y-intercept x + 2y = 14 {the given equation} 2y = -x + 14 {subtracted x from each side} y = (-1/2)x + 7 {divided each side by 2} slope = -1/2 (-8,0) and m = -1/2 are the point and the slope. Substitute into slope-intercept form to get the y-intercept. y = mx + b {slope-intercept form} 0 = (-1/2)(-8) + b {substituted the point and slope into slope-intercept form} 0 = 4 + b {multiplied} b = -4 {subtracted 4 from each side} y-intercept = -4 Substitute the slope, -1/2, and the y-intercept, -4, back into slope-intercept form. y = mx + b {slope-intercept form} y = (-1/2)x - 4 is the equation of the line. Ask Algebra House
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