Solve -x + 2y = 10 and -2x + 3y = 18 using the substitution method.
Get one of the equations solved for either x or y, so that you can substitute into the other equation.
-x + 2y = 10 -----> -x = -2y + 10 -----> x = 2y - 10 {solved first equation for x} -2x + 3y = 18 Substitute (2y - 10), in for x, into second equation. -2(2y - 10) + 3y = 18 {substituted (2y - 10), in for x, into second equation} -4y + 20 + 3y = 18 {used distributive property} -y + 20 = 18 {combined like terms} -y = -2 {subtracted 20 from each side} y = 2 {divided each side by -1} Substitute 2, in for y, into one of the two equations to solve for x. -x + 2y = 10 {first original equation} -x + 2(2) = 10 {substituted 2, in for y, into first original equation} -x + 4 = 10 {multiplied 2 by 2} -x = 6 {subtracted 4 from each side} x = -6 {divided each side by -1} x = -6 and y = 2 Ask Algebra House
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