Solve x + 2y = 10 and 2x + 3y = 18 using the substitution method.
Get one of the equations solved for either x or y, so that you can substitute into the other equation.
x + 2y = 10 > x = 2y + 10 > x = 2y  10 {solved first equation for x} 2x + 3y = 18 Substitute (2y  10), in for x, into second equation. 2(2y  10) + 3y = 18 {substituted (2y  10), in for x, into second equation} 4y + 20 + 3y = 18 {used distributive property} y + 20 = 18 {combined like terms} y = 2 {subtracted 20 from each side} y = 2 {divided each side by 1} Substitute 2, in for y, into one of the two equations to solve for x. x + 2y = 10 {first original equation} x + 2(2) = 10 {substituted 2, in for y, into first original equation} x + 4 = 10 {multiplied 2 by 2} x = 6 {subtracted 4 from each side} x = 6 {divided each side by 1} x = 6 and y = 2 Ask Algebra House
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