Can you explain to me how to solve the following problem?
Isaac bought school shirts for $35 each and school pants for $49 each. If he buys 9 items and his total cost is $357, how many shirts did he buy? I solved it with trial and error, but I know there is an algebraic method. Thank you.
Make a system of two equations. Let the variables represent what you do not know, the number of shirts and
the number of pants. x = number of shirts y = number of pants x + y = 9 {he buys 9 items} 35x + 49y = 357 {shirts are $35 each, pants are $49 each, the total is 357} Use the elimination method to solve the system, multiplying the top equation by -35, and then adding the two equations together. This will eliminate the x. You could also multiply the top equation by -49 and add together, or even use the substitution method. -35x - 35y = -315 {multiplied first equation by -35} 35x + 49y = 357 {second equation stays the same} ---------------- 14y = 42 {added the two equations together} y = 3 {divided each side by 14} x + y = 9 {first original equation} x + 3 = 9 {substituted 3, in for y, into first equation} x = 6 {subtracted 3 from each side} He bought 6 shirts and 3 pants Ask Algebra House
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