Solve the equation for x:
6 12 ——— = —— x  1 x²  1 6 12 ——— = —— x  1 x²  1 6x²  6 = 12x  12 {crossmultiplied} 6x²  12x + 6 = 0 {subtracted 12x and added 12 to each side} 6(x²  2x + 1) = 0 {factored 6 out of left side} x²  2x + 1 = 0 {divided each side by 6} (x  1)(x  1) = 0 {factored into two binomials} x  1 = 0 {set equal to zero} x = 1 {solved for x} However, when you substitute 1 back in for x, it makes the denominators equal to zero, which is undefined. = no solution Ask Algebra House
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