Solve the equation for x:
6 12 ——— = ——-- x - 1 x² - 1 6 12 ——— = ——-- x - 1 x² - 1 6x² - 6 = 12x - 12 {cross-multiplied} 6x² - 12x + 6 = 0 {subtracted 12x and added 12 to each side} 6(x² - 2x + 1) = 0 {factored 6 out of left side} x² - 2x + 1 = 0 {divided each side by 6} (x - 1)(x - 1) = 0 {factored into two binomials} x - 1 = 0 {set equal to zero} x = 1 {solved for x} However, when you substitute -1 back in for x, it makes the denominators equal to zero, which is undefined. = no solution Ask Algebra House
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