Set f(x), the y-value, equal to zero, and then solve for x.
f(x) = (x² + 2x - 8)(x - 6) (x² + 2x - 8)(x - 6) = 0 {set f(x) equal to zero} (x + 4)(x - 2)(x - 6) = 0 {factored x² + 2x - 8 into two binomials} x + 4 = 0 or x - 2 = 0 or x - 6 = 0 {set each factor equal to zero} x = -4 or x = 2 or x = 6 {solved each equation for x} (2,0) , (6,0), and (-4,0) are the zeros of the function. Ask Algebra House
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