Ben has a toy light saber, and he wants to construct one proportionally smaller than his. The light on his is 33 in, and the handle is 9 in. If the light on the smaller version is 11 in, how long should the handle be?
Set up and solve a proportion
x = handle length 9/33 = 11/x 9x = 363 {crossmultiplied} x = 40.3 {divided each side by 9} The handle should be approximately 40.3 inches. Ask Algebra House
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