(x + 11i)(x  11i)
= x(x) + x(11i) + 11i(x) + 11i(11i) {multiplied using the distributive property or FOIL method}
= x² + 11xi + 11xi + 121i² {multiplied through} = x² + 22xi + 121(1) {combined like terms, and i² is 1} = x² + 22xi  121 {multiplied 121 by 1} Ask Algebra House
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