Determine the equation of a line in pointslope form that passes through (3, 4) and is perpendicular
to the line 2x + 3y = 15.
Get the given equation in slopeintercept form, y = mx + b.
2x + 3y = 15 3y = 2x  15 {added 2x to each side} y = (2/3)x  5 {divided each side by 3} slope = 2/3 Perpendicular lines have slopes which are negative reciprocals of each other. perpendicular slope is 3/2 slope is 3/2 and point is (3,4) Substitute point and slope into pointslope form. y  y1 = m(x  x1) {pointslope form} y  (4) = (3/2)(x  3) {substituted into pointslope form} y + 4 = (3/2)(x  3) {simplified double negative signs} Ask the House
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