A furniture shop refinishes tables. Employees use one of two methods to refinish each table. Method I takes 0.5 hours and the material costs $10. Method II takes 2 hours, and the material costs $6. Next week, they plan to spend 175 hours in labor and $1120 in material for refinishing tables. How many tables should they plan to refinish with each method?
x = number of tables with method 1
y = number of tables with method 2 0.5x + 2y = 175 {hours making each table} 10x + 6y = 1120 {cost making each table} 1.5x  6y = 525 {multiplied top equation by 3} 10x + 6y = 1120 {bottom equation stays the same} ——————— 8.5x = 595 {added the 2 equations} x = 70 {divided each side by 8.5} 10x + 6y = 1120 {second equation from above} 10(70) + 6y = 1120 {substituted 70, in for x, into second equation} 700 + 6y = 1120 {multiplied 10 by 70} 6y = 420 {subtracted 700 from each side} y = 70 {divided each side by 6} 70 tables using method 1 70 tables using method 2 Ask the House
0 Comments
Your comment will be posted after it is approved.
Leave a Reply. 
Latest Videos
Archives
April 2021
