Steve travels 5 times as fast as Kevin. Traveling in opposite directions, they are 390 miles apart after 5 hours. Find their rates of travel.
This is a distance, rate, time problem.
d = rt distance = rate x time Kevin distance = d {unknown} rate = r time = 5 {they travel for 5 hours} d = 5r {distance equals rate x time} Steve distance = d {unknown} rate = 5r {Steve travels 5 times as fast as Kevin} time = 5 {they travel for 5 hours} d = 5r(5) {distance equals rate x time} d = 25r {multiplied 5r by 5} They are traveling in opposite directions. After 5 hours their distances add up to 390. Add their distances together and set equal to 390. 5r + 25r = 390 {added distances and set equal to 390} 30r = 390 {combined like terms} r = 13 {divided each side by 30} 5r = 65 {substituted 13, in for r, into 5r} Kevin’s rate is 13 mph Steve’s rate is 65 mph Ask Algebra House
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