A rectangular auditorium seats 2408 people. The number of seats in each row exceeds the numbers of rows by 13. Find the number of seats in each row.
x = the number of rows
x + 13 = number of seats in each row {the number of seats in each row exceeds the number of rows by 13} (number of seats in each row) x (number of rows) = total number of seats x(x + 13) = 2408 {multiplied number of rows by the number of seats in each row and set equal to total seats} x² + 13x = 2408 {used distributive property} x² + 13x  2408 = 0 {subtracted 2408 from each side} (x + 56)(x  43) = 0 {factored into two binomials} x + 56 = 0 or x  43 = 0 {set each factor equal to zero} x = 56 or x = 43 {solved each equation for x} x = 43 only {the number of rows cannot be 56} x + 13 = 43 + 13 = 56 {substituted 43, in for x, into x + 13} number of seats in each row = 56 Ask Algebra House
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