The two longest sides of a pentagon are each 3 times as long as the shortest side. The other sides are each 8 m longer than the shortest side. Find the length of each side if the perimeter is 79 m. Use x = shortest side
x = shortest side
3x = one of the longest sides 3x = other longest side x + 8 = other side x + 8 = other side x + 3x + 3x + x + 8 + x + 8 = 79 {perimeter, which is 79, equals all sides added together} 9x + 16 = 79 {combined like terms} 9x = 63 {subtracted 16 from each side} x = 7 {divided each side by 9} 3x = 21 {substituted 7, in for x, into 3x} x + 8 = 15 {substituted 7, in for x, into x + 8} sides are 7, 15, 15, 21, and 21 Ask the House
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