The two longest sides of a pentagon are each 3 times as long as the shortest side. The other sides are each 8 m longer than the shortest side. Find the length of each side if the perimeter is 79 m. Use x = shortest side

x = shortest side

3x = one of the longest sides

3x = other longest side

x + 8 = other side

x + 8 = other side

x + 3x + 3x + x + 8 + x + 8 = 79 {perimeter, which is 79, equals all sides added together}

9x + 16 = 79 {combined like terms}

9x = 63 {subtracted 16 from each side}

x = 7 {divided each side by 9}

3x = 21 {substituted 7, in for x, into 3x}

x + 8 = 15 {substituted 7, in for x, into x + 8}

3x = one of the longest sides

3x = other longest side

x + 8 = other side

x + 8 = other side

x + 3x + 3x + x + 8 + x + 8 = 79 {perimeter, which is 79, equals all sides added together}

9x + 16 = 79 {combined like terms}

9x = 63 {subtracted 16 from each side}

x = 7 {divided each side by 9}

3x = 21 {substituted 7, in for x, into 3x}

x + 8 = 15 {substituted 7, in for x, into x + 8}

**sides are 7, 15, 15, 21, and 21**__Ask the House__